# This script has several errors. Your goal is to find the errors and fix the program so it will…

This script has several
errors. Your goal is to find the errors and fix the program so it will work.
Use the error messages you get as a clue to fix the problems.

After you correct all the syntax errors and
runtime errors, and the program runs without error messages, you will find
there is also a logic error: The calculated value is over three times too
large! It should be a little less than 1000 Watts per square meter. Compare the
formula in the program to the formula given below to identify and correct this
last error.

This program calculates
the heat transfer rate per unit area of a furnace wall. The basic heat transfer
equation for conduction is given by q = KA(T1 – T2)/d, where q is the heat
transfer rate, k is the thermal conductivity (a property of the material), T2
and T1 are the temperatures on each side of the wall, A is the surface area of
the items in contact, and d is the thickness (depth). In this case we want heat
transfer rate per unit area so:

HeatTransferPerArea =
q/A = k(T2-T1)/d

If you do this
calculation on your own, the units need to line up. Make sure the units in k go
with the units for temperature and length that you use for A, d and T.

Script Save C Reset
MATLAB Documentation 1

% Initialize variables 2

Thermal Conductivity=8.3;
% fire clay for a furnace wall in Watts/(meter*Kelvin) 3

TempInside=650; % This
is in C, which I can get away with because delta C = delta K 4

TempOutside=150; % also in C 5

Thickness = 0.1524; % 6
inches in meters 6 7

HeatTransferPerArea=(Thermal
Conductivtiy + (TempInside-TempOutside))/Thickness; 8 9

fprint(Heat transfer per
area is %.2f Watts/square metern, HeatTransferPerArea); 10

? Run Script

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